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(D) In Young's Double Slit Experiment,the fringe width $\beta$ is given by $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D

Vedclass · Accepted Answer

Both $(B)$ and $(C)$.

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(D) In Young's Double Slit Experiment,the fringe width $\beta$ is given by $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the slits and the screen,and $d$ is the distance between the two slits.From this formula,it is clear that $\beta \propto \frac{1}{d}$,meaning the fringe width changes in inverse proportion to $d$. This confirms statement $(B)$.The position of the $n$-th minimum is given by $y_n = (2n - 1) \frac{\lambda D}{2d}$. Since $y_n$ depends on $d$,changing $d$ will shift the positions of all minima on the screen. This confirms statement $(C)$.Therefore,both statements $(B)$ and $(C)$ are correct.

The figure shows a schematic diagram of the arrangement of Young's Double Slit Experiment. If the distance $d$ is varied,then identify the correct statement.

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